Titre: Problem avec un php script de recherche de Bdd mysql
Posté par: jhondoe144 le le 06-12-2010 a 13:05:29
Bonjour a tous ,
j'aimerai que l'on m'aide pour un script de recherche de base de donnees que j 'ai trouve sur le net le problem c'est que la pagination ne fonctione pas si quelqu'un peut m'aider se serai super vue que je ne suis pas un expert en php mais j ai kant meme de bonne notion pour pouvoir le modifier et m'en servire par la suite voila le script :
Merci de votre aide.
<?php
// Get the search variable from URL
$var = @$_GET['q'] ; $trimmed = trim($var); //trim whitespace from the stored variable
// rows to return $limit=10;
// check for an empty string and display a message. if ($trimmed == "") { echo "<p>Please enter a search...</p>"; exit; }
// check for a search parameter if (!isset($var)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; }
//connect to your database ** EDIT REQUIRED HERE ** mysql_connect("localhost","username","password"); //(host, username, password)
//specify database ** EDIT REQUIRED HERE ** mysql_select_db("database") or die("Unable to select database"); //select which database we're using
// Build SQL Query $query = "select * from the_table where 1st_field like \"%$trimmed%\" order by 1st_field"; // EDIT HERE and specify your table and field names for the SQL query
$numresults=mysql_query($query); $numrows=mysql_num_rows($numresults);
// If we have no results, offer a google search as an alternative
if ($numrows == 0) { echo "<h4>Results</h4>"; echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>";
// google echo "<p><a href=\"http://www.google.com/search?q=" . $trimmed . "\" target=\"_blank\" title=\"Look up " . $trimmed . " on Google\">Click here</a> to try the search on google</p>"; }
// next determine if s has been passed to script, if not use 0 if (empty($s)) { $s=0; }
// get results $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query");
// display what the person searched for echo "<p>You searched for: "" . $var . ""</p>";
// begin to show results set echo "Results"; $count = 1 + $s ;
// now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["1st_field"];
echo "$count.) $title" ; $count++ ; }
$currPage = (($s/$limit) + 1);
//break before paging echo "<br />";
// next we need to do the links to other results if ($s>=1) { // bypass PREV link if s is 0 $prevs=($s-$limit); print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< Prev 10</a>  "; }
// calculate number of pages needing links $pages=intval($numrows/$limit);
// $pages now contains int of pages needed unless there is a remainder from division
if ($numrows%$limit) { // has remainder so add one page $pages++; }
// check to see if last page if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {
// not last page so give NEXT link $news=$s+$limit;
echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>"; }
$a = $s + ($limit) ; if ($a > $numrows) { $a = $numrows ; } $b = $s + 1 ; echo "<p>Showing results $b to $a of $numrows</p>"; ?> |
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